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4个数字的混合运算得固定结果的可能性

作者 佚名技术 来源 服务器技术 浏览 发布时间 2012-07-11
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if (m1 == "-" and m2 == "*" and m3 == "+") {
result = num1-num2*num3+Number(num4);
}
if (m1 == "-" and m2 == "*" and m3 == "-") {
result = num1-num2*num3-num4;
}
if (m1 == "-" and m2 == "*" and m3 == "*") {
result = num1-num2*num3*num4;
}
if (m1 == "-" and m2 == "*" and m3 == "/") {
result = num1-num2*num3/num4;
}
//------------------------------
if (m1 == "-" and m2 == "/" and m3 == "+") {
result = num1-num2/num3+Number(num4);
}
if (m1 == "-" and m2 == "/" and m3 == "-") {
result = num1-num2/num3-num4;
}
if (m1 == "-" and m2 == "/" and m3 == "*") {
result = num1-num2/num3*num4;
}
if (m1 == "-" and m2 == "/" and m3 == "/") {
result = num1-num2/num3/num4;
}
//--------------------------------
if (m1 == "*" and m2 == "+" and m3 == "+") {
result = num1*num2+Number(num3)+Number(num4);
}
if (m1 == "*" and m2 == "+" and m3 == "-") {
result = num1*num2+Number(num3)-num4;
}
if (m1 == "*" and m2 == "+" and m3 == "*") {
result = num1*num2+num3*num4;
}
if (m1 == "*" and m2 == "+" and m3 == "/") {
result = num1*num2+num3/num4;
}
//---------------------------------
if (m1 == "*" and m2 == "-" and m3 == "+") {
result = num1*num2-num3+Number(num4);
}
if (m1 == "*" and m2 == "-" and m3 == "-") {
result = num1*num2-num3-num4;
}
if (m1 == "*" and m2 == "-" and m3 == "*") {
result = num1*num2-num3*num4;
}
if (m1 == "*" and m2 == "-" and m3 == "/") {
result = num1*num2-num3/num4;
}
//----------------------------------
if (m1 == "*" and m2 == "*" and m3 == "+") {
result = num1*num2*num3+Number(num4);
}
if (m1 == "*" and m2 == "*" and m3 == "-") {
result = num1*num2*num3-num4;
}
if (m1 == "*" and m2 == "*" and m3 == "*") {
result = num1*num2*num3*num4;
}
if (m1 == "*" and m2 == "*" and m3 == "/") {
result = num1*num2*num3/num4;
}
//---------------------------------
if (m1 == "*" and m2 == "/" and m3 == "+") {
result = num1*num2/num3+Number(num4);
}
if (m1 == "*" and m2 == "/" and m3 == "-") {
result = num1*num2/num3-num4;
}
if (m1 == "*" and m2 == "/" and m3 == "*") {
result = num1*num2/num3*num4;
}
if (m1 == "*" and m2 == "/" and m3 == "/") {
result = num1*num2/num3/num4;
}
//----------------------------------
if (m1 == "/" and m2 == "+" and m3 == "+") {
result = num1/num2+Number(num3)+Number(num4);
}
if (m1 == "/" and m2 == "+" and m3 == "-") {
result = num1/num2+Number(num3)-num4;
}
if (m1 == "/" and m2 == "+" and m3 == "*") {
result = num1/num2+num3*num4;
}
if (m1 == "/" and m2 == "+" and m3 == "/") {
result = num1/num2+num3/num4;
}
//----------------------------------
if (m1 == "/" and m2 == "-" and m3 == "+") {
result = num1/num2-num3+Number(num4);
}
if (m1 == "/" and m2 == "-" and m3 == "-") {
result = num1/num2-num3-num4;
}
if (m1 == "/" and m2 == "-" and m3 == "*") {
result = num1/num2-num3*num4;
}
if (m1 == "/" and m2 == "-" and m3 == "/") {
result = num1/num2-num3/num4;
}
//-----------------------------------
if (m1 == "/" and m2 == "*" and m3 == "+") {
result = num1/num2*num3+Number(num4);
}
if (m1 == "/" and m2 == "*" and m3 == "-") {
result = num1/num2*num3-num4;
}
if (m1 == "/" and m2 == "*" and m3 == "*") {
result = num1/num2*num3*num4;
}
if (m1 == "/" and m

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